Web Reference: # Return True if the given string contains an appearance of "xyz" where the # xyz is not directly preceeded by a period (.). So "xxyz" counts but "x.xyz" # does not. def xyz_there (str): if str [:3] == "xyz": return True for i in range (1, len (str) - 2): if str [i-1] != "." and str [i:i+3] == "xyz": return True return False This exercise was taken from codingbat.com and has been adapted for the Python language. There are many great programming exercises there, but the majority are created for Java. Your code does not work for strings where 'xyz' is in the middle of the string (i.e. not at the start of the end of the string). See for example the result for 'testxyzstring': xyz_there("testxyzstring") returns False.
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String 2 Xyz There Python Net Worth 2026: Salary, Income & Wealth Net Worth & Biography
Estimated Worth: $57M - $88M
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Last Updated: April 7, 2026
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