Resolving Php Warning In Array 7 ROKMiV VE

Web Reference: The second condition fails because in_array () is case-sensitive, so the program above will display: An empty array does not cause that error, the problem is that you are trying to iterate trough something that is not an array. You could add a check using is_array function. Learn how to fix the `PHP Warning: in_array () expects parameter 2 to be array, string given` issue in your PHP code.

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