Web Reference: I am a C guy and I'm trying to understand some C++ code. I have the following function declaration: Dec 28, 2015 · Closed 10 years ago. These are two simple samples in C++ written on Dev-cpp C++ 5.4.2: A fine question, but a little too broad (IMO). That's called the scope-resolution operator, and your search term for further learning is scope. All those names (cout, member functions of A) are defined in scopes and you have to resolve the scope (that is, tell the compiler where to look) with ::.
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